lib.sh: remove rmgit()

We don't need to call it from git.sh, because it's
only being done when building a release anyway,
and we already run rmgit when doing a release.

The function itself is only two simple fx_ calls,
so we can just do that from build_release().

Signed-off-by: Leah Rowe <leah@libreboot.org>

include/git.sh

@@ -57,9 +57,6 @@ git_prep()
 		dx_ fetch_submodule "$mdir/module.list"
 	fi
 
-	[ "$_loc" != "$XBMK_CACHE/repo/$project" ] && \
-	    [ "$XBMK_RELEASE" = "y" ] && rmgit "$tmpgit"
-
 	[ "$_loc" = "${_loc%/*}" ] || x_ mkdir -p "${_loc%/*}"
 	x_ mv "$tmpgit" "$_loc"
 }

include/lib.sh

@@ -29,12 +29,6 @@ mktarball()
 	x_ tar -c "$1" | xz -T$XBMK_THREADS -9e > "$2" || err "mktarball2, $1"
 }
 
-rmgit()
-{
-	fx_ "x_ rm -Rf" x_ find "$1" -name ".git"
-	fx_ "x_ rm -Rf" x_ find "$1" -name ".gitmodules"
-}
-
 e()
 {
 	es_t="e" && [ $# -gt 1 ] && es_t="$2"

include/release.sh

@@ -37,7 +37,8 @@ build_release()
 	x_ cd "$relsrcdir"
 
 	x_ ./mk -f
-	rmgit .
+	fx_ "x_ rm -Rf" x_ find . -name ".git"
+	fx_ "x_ rm -Rf" x_ find . -name ".gitmodules"
 	x_ mv src/docs docs
 	) || err "can't create release files"